Which has the smallest size?

{A l}^{3 +}

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{M g}^{2 +}

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P^{5 +}

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{N a}^{+}

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Solution

The correct option is C $P^{5 +}$
Ionic size varies inversely with nuclear charge. Higher the nuclear charge, smaller the radii. Thus $P^{5 +}$ because of the high nuclear charge, has the smallest size.

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Similar questions

$N a^{+} . M g^{2 +}, A l^{3 +}$ and $S i^{4 +}$ are isoelectronic. The order of their ionic size is

N a^{+}

M g^{2 +}

A l^{3 +}

S i^{4 +}

N a^{+}, M g^{2 +}

A l^{3 +}, N a^{+}

M g

M g^{2 +}

A l^{3 +}

N a^{+}, M g^{2 +}, A l^{3 +}

S i^{4 +}

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