Question

Which have same number of atoms $16$ of $O_2$, $4$ of Hydrogen, $44$ of $C{O}_2$, $28$ of Nitrogen and $32$ of $O_2$

Answer 1

$44$ of $C{O}_2=1$ mole

$=6.022\times {10}^{23}C{O}_2$ molecules

$1C{O}_2=3$ atom

$\star 1mole=44$ of $C{O}_2$

$=3\times 6.022\times {10}^{23}$ atom

$\star 28$ of $N_2=1$ mole

$1N_2=2$ atom

1 mole of $N_2=2\times 6.022\times {10}^{23}$

$=12.044\times {10}^{23}$

$\star 32$ of $O_2=1$ mole

$1O_2=2$ atom

1 mole of $O_2=2\times 6.022\times {10}^{23}$

$=12.044\times {10}^{23}$atom