Which intermediate is formed during the mechanism of the given reaction sequence?

Carbocation

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Carbanion

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Radical

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Carbene

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Solution

The correct option is A Carbocation
The pi electrons of carbon carbon double bond are donated to proton to form tertiary carbocation. The pi elctrons of another carbon carbon double bond are donated to this carbocation to form five membred ring. This is followed by the nucleophilic attack of chloride ion to form the product.

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(A)

{C H}_{3} {C H}_{2} - N = N - {C H}_{2} {C H}_{3} h e a t - - \to (A) + N_{2}

S_{N} 1

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