Which ion has tetrahedral geometry?

[F e {(C O)}_{5}]

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{[C o {(N H_{3})}_{6}]}_{6}^{2 +}

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{[N i C l_{4}]}_{4}^{2 -}

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{[N i {(C N)}_{4}]}_{4}^{2 -}

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Solution

The correct option is C ${[N i C l_{4}]}_{4}^{2 -}$
$[N i C l_{4}]^{2}, N i^{+ 2} d^{10}$ configuration with high spin complex so $s p^{3}$ hybridization and tetrahedral geometry. $[N i (C N)_{4}]^{2}, d s p^{2}$ hybridization.

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Similar questions

Explain on the basis of valence bond theory that [Ni(CN)₄]²⁻ ion with square

planar structure is diamagnetic and the [NiCl₄]²⁻ ion with tetrahedral geometry is paramagnetic.

[N i (C N)_{4}]^{2 -}, [N i C l_{4}]^{2 -}

[N i (C O)_{4}]

[N i (C N)_{4}]^{2 -}

[N i (C N)_{4}]^{- 2}

[N i C l_{4}]^{- 2}

e^{-}

[N i C N_{4}]^{- 2}

[N i C l_{4}]^{- 2}

[N i (C O)_{4}]

[N i C l_{4}]^{2 -}

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