Which is a diad form of tautomerism?

H - O - N = O ⇌ H - O ↑ N = O

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C H_{3} - O ↑ N = O ⇌ C H_{2} = O ↑ N - O H

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H - O - C \equiv N ⇌ O = C = N H

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All of these

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Solution

The correct option is A $H - O - N = O ⇌ H - O ↑ N = O$
Tautomerism is an equilibrium between two forms of a compound. One of which can be more stable than other depending upon condition.
For example: in keto-enol tautomerism, maximum time keto form remains more stable, but there are some cases where enol form is also stable.

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Similar questions

Q. Which of the following is not the pair of resonance structures?

I . H N = C = O \leftrightarrow H - O - C \equiv N

I I . ¯ N = C = O \leftrightarrow N \equiv C - O^{-}

I I I . C H_{3} - O | | C - ¯ C H_{2} \leftrightarrow C H_{3} -^{-} C = C H_{2}

I V . C H_{3} - O | | C - C H_{3} \leftrightarrow C H_{3} - O H | C = C H_{2}

Q. Find

A, B

and

C

in the following reactions:

$N H_{3} + A + C O_{2} \to {(N H_{4})}_{2} C O_{3}$

${(N H_{4})}_{2} C O_{3} + H_{2} O + B \to N H_{4} H C O_{3}$

$N H_{4} H C O_{3} + N a C l \to N H_{4} C l + C$

H - O - C = N (C y a n i c a c i d), H - N = C = O (I s o c y a n i c a c i d)

Loss of proton from these two acids produces:

$S n C l_{2} .2 H_{2} O Δ \to ? - + H C l + H_{2} O$

Balance the following equations :

(a) $N_{2} + H_{2} \to N H_{3}$

(b) $H_{2} + O_{2} \to H_{2} O$

(d) $C O + O_{2} \to C O_{2}$

(e) $Z n + H C I \to Z n C l_{2} + H_{2}$

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