Which is a stronger base - $⊖ P H_{2}$ or $⊖ N H_{2}$ ?

⊖ P H_{2}

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⊖ N H_{2}

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Both have equal basicity

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Neither is a base

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Solution

The correct option is B $⊖ N H_{2}$
The atomic size of $N$ is smaller than that of $P$ . Hence, $N - H$ bond is smaller (and stronger) than $P - H$ bond. Hence, bond energy $(N - H > P - H)$ . Therefore, $⊖ N H_{2}$ has a strong tendency to accept proton. Hence, $⊖ N H_{2}$ is a stronger base than $⊖ P H_{2}$ .

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