Question

Which is/are the correct statement(s) about $1.7\text{g}$ of $N{H}_3$?

• A. It contains 0.3 mol of H-atom
• B. It contains $2.408\times {10}^{23}$ atoms
• C. Mass % of hydrogen is 17.65%
• D. Vapour density of $N{H}_3$ is 17

Answer 1

Answer: (A), (B), (C)

Mass % of hydrogen is 17.65%

Moles of $N{H}_3=\frac{1.7}{17}=0.1$ ; Moles of $H$ atom $=0.3$
Total atoms $=0.4\times 6.02\times {10}^{23}=2.408\times {10}^{23}$
Mass $\%H=\frac{3\times 1}{17}\times 100=17.65\%$