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VBT vs CFT - Octahedral Complexes

Which is/are ...

Question

Which is/are used as ligand in complexes?

A

C N^{-}

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B

C O

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C

Both (A) and (B)

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D

None of these

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Solution

The correct option is C Both (A) and (B)
Both $C O$ and $C N^{-}$ have lone pair of electron for donation so they both can act as ligand.
$N i + 4 C O \to N i (C O)_{4}$
$N i + 4 C N^{-} \to N i (C N)_{4}^{2 -}$

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Similar questions

[N i (C O)_{4}]

[N i (C N)_{4}]^{2 -}

are diamagnetic. The hybridizations of nickel in these complexes, respectively, are:

[N i (C O)_{4}]

[N i (C N)_{4}]^{2 -}

are diamagnetic. The hybridisations of nickel in these complexes respectively are

[N i (C O)_{4}]

[N i (C N)_{4}]^{2 -}

are diamagnetic. The types of hybridisation of

N i

in these complexes are respectively:

C r^{3 +}

form four complexes with four different ligands which are

[C r (C l)_{6}]^{3 -}, [C r (H_{2} O)_{6}]^{3 +}, [C r (N H_{3})_{6}]^{3 +}

[C r (C N)_{6}]^{3 -}

. The order of CFSE

(Δ_{o})

in these complexes is in the order :

Q. What is the total number of isomers including stereoisomers that have the formula

K_{3} [C o (C N)_{6}]

? (All are octahedral complexes with

C o^{3 +}

and ambidentate ligand

C N^{-}

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