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B
MgCO3
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C
BaCO3
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D
Equally
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Solution
The correct option is DMgCO3 MCO3→MO+CO2−394.4 Mg−1028.2−568.964.9Ca−1129.2603.4165.9Ba−1134.4−520.4219.6 As second value is negative for both Ba and Ca so they are more stable and MgCO3 is least stable so it will decompose easily.