Which is expected to react most readily with bromine water?

C H_{3} C H_{2} C H_{3}

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C H_{2} = C H_{2}

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C H \equiv C H

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C H_{3} - C H = C H_{2}

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Solution

The correct option is B $C H_{3} - C H = C H_{2}$

Alkenes are more reactive than alkyne and alkane towards $B r_{2}$ .

In alkenes, more substituted alkenes are reactive towards $B r_{2} / C l_{2}$ .

Among $B$ and $D$ alkene, $D$ is more substituted than $B$ , hence $D$ is expected to react more readily with bromine water.

Hence, option $D$ is the answer.

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Similar questions

A . C H_{3} - C H = C H_{2} + H C l ⟶ C H_{3} - C | C l H - C H_{3}

B . C H_{3} - C H = C H_{2} + H B r ⟶ C H_{3} - C H_{2} - C H_{2} B r

C . C H_{3} - C H = C H_{2} + H B r p e r o x i d e - ---- \to C H_{3} - C H_{2} - C H_{2} - B r

D . C H_{3} - C H = C H_{2} + H I p e r o x i d e - ---- \to C H_{3} - C | I H - C H_{3}

130^{\circ} C

A g N O_{3}

C H_{2} = C H - C \equiv C H

C H \equiv C - C \equiv C H

C H_{3} - C H = C H_{2}

C H_{2} = C H - C H = C H_{2}

C H_{3} - C H = C H - C H_{2} - O H | C H - C H_{3} ⟶ C H_{3} - C H = C H - C H_{2} - C O O H

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