Which is greater?
$17 o r - 8$

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Solution

Comparing the integers
Given integers are $17 a n d - 8$
We know that a positive integer is always greater than a negative integer.
$17$ is a positive integer and $- 8$ is a negative integer
Hence $17$ is greater than $- 8$ or $17 > - 8$

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Which is greater in the following pair- $- 4, - 17$ ?

\frac{1}{4!} + \frac{1}{5!} = \frac{x}{6!}

\frac{x}{10!} = \frac{1}{8!} + \frac{1}{9!}

\frac{1}{6!} + \frac{1}{7!} = \frac{x}{8!}

3

0.8

31^{12} o r 17^{17}

(31)^{12}

(17)^{17}

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