Which is incorrect reaction in following :-

G l u c o s e B r_{2} w a t e r - ----- \to G l u c o n i c a c i d

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G l u c o s e N H_{2} O H - ---- \to G l u c o n i c a c i d

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G l u c o s e N a - \frac{H g}{H_{2} O} - ----- \to S o r b i t o l

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G l u c o s e A g_{2} O - -- \to G l u c o n i c a c i d

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Solution

The correct option is B $G l u c o s e N H_{2} O H - ---- \to G l u c o n i c a c i d$
Glucose with $N H_{2} O H$ forms oxime.

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