You visited us 1 times! Enjoying our articles? Unlock Full Access!

Classification

Which is inco...

Question

Which is incorrectly given according to order indicated ?

F_{2} > C l_{2} > B r_{2} > I_{2}

: Oxidising power

No worries! We‘ve got your back. Try BYJU‘S free classes today!

H I > H B r > H C l > H F

: Acidic strength

No worries! We‘ve got your back. Try BYJU‘S free classes today!

F_{2} > C l_{2} > B r_{2} > I_{2}

: Bond dissociation enthalpy

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

H F > H I > H B r > H C l

: Boiling point

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $F_{2} > C l_{2} > B r_{2} > I_{2}$ : Bond dissociation enthalpy
Bond dissociation energy of $C l$ is highest and the order is
$C l_{2} > B r_{2} > F_{2} > I_{2}$
$\frac{1 e V}{a t o m} = 1.602 \times 10^{- 22} \frac{k J}{m o l}$
This is due to the small size and high electronegativity of $F$ , it suffers inter-electronic repulsion and hence has a low value of bond dissociation enthalpy.

Suggest Corrections

Similar questions

F_{2}, C l_{2}, B r_{2}, I_{2}

H F, H C l, H B r, H I

N H_{3}, P H_{3}, A s H_{3}, S b H_{3}, B i H_{3}

Arrange the following in the order of property indicated for each set:

$F_{2}, C l_{2}, B r_{2}, I_{2}$ - increasing bond dissociation enthalpy.

HF,HCl, HBr, HI- Increasing acid strength.

$N H_{3}, P H_{3}, A s H_{3}, S b H_{3}, B i H_{3}$ - increasing base strength.

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

H O C l > H C l O_{2} > H C l O_{3} > H C l O_{4} :

H O C l > H C l O_{2} > H C l O_{3} > H C l O_{4} :

(x^{2} + y^{2})

x

y

H F, H C l, H B r, H I

I_{2}, {B r}_{2}, {C l}_{2}, F_{2}

I_{2} < {B r}_{2} < {C l}_{2} < F_{2}

Join BYJU'S Learning Program