Question

Which is more ionic ${\mathrm{PbCl}}_2\mathrm{or}{\mathrm{PbCl}}_4$?

Answer 1

1. Lead is the chemical element that is found in the periodic table.
2. The atomic number of Lead is $82$ and the mass number is$207.2$.
3. Lead possesses two types of oxidation state$+2\mathrm{and}+4$.
4. The charge present on ${\mathrm{PbCl}}_2$ is $+2$ and on ${\mathrm{PbCl}}_4$ is$+4.$
5. According to Fajan's rule, greater will be the charge on cation, and more will be its ability to polarize the bonding electrons towards itself.
6. Therefore, in ${\mathrm{PbCl}}_4$greater charge is present and so it shows covalent characters.
7. Due to the lesser charge present${\mathrm{PbCl}}_2$, it will not able to polarise the bonded electrons and so it forms an ionic compound.
8. Thus, ${\mathrm{PbCl}}_2$ is more ionic compared with ${\mathrm{PbCl}}_4$