Which is more stable in the below given pair?

$M n^{2 +}$ , $M n^{3 +}$ and $M n O_{4}^{-}$

M n^{3 +}

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M n O_{4}^{-}

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M n^{2 +}

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None of these

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Solution

The correct option is B $M n O_{4}^{-}$
With an increase in the oxidation state, the stability increases.

Hence, O.N. of $M n^{2 +}$ = +2
O.N. of $M n^{3 +}$ = +3
O.N. of ${M n O_{4}}^{-}$ = +7

Among $M n^{2 +}$ , $M n^{3 +}$ and $M n O_{4}^{-}$ , the ion with maximum stability is $M n O_{4}^{-}$ .

Suggest Corrections

Similar questions

Which is more stable in the below given pair?

M n O_{4}^{-}

and

R e O_{4}^{-}

While $F e^{3 +}$ is stable, $M n^{3 +}$ is not stabe in acid solution because:
$(M n^{3 +} + e^{-} \to M n^{2 +}, E^{\circ} = 1.5 V; O_{2} + 4 H^{+} + 4 e^{-} \to 2 H_{2} O, E^{\circ} = + 1.23 V; F e^{3 +} + e^{-} \to F e^{2 +}, E^{\circ} = 0.77 V)$