Question

Which is more stable in the below given pair?

$V^{2+}$ ______ $V{O}_4^{3-}$

• A. $V^{2+}=V{O}_4^{3-}$
• B. $V^{2+}<V{O}_4^{3-}$
• C. $V^{2+}>V{O}_4^{3-}$
• D. None of these

Answer 1

The correct option is B $V^{2+}<V{O}_4^{3-}$

$V^{2+}<V{O}_4^{3-}$is correct because in $V{O}_4^{3-}$. $V$ is in maximum oxidation state that is $+5$.

Generally, transition elements in its higher oxidation state are more stable.

Hence option B is correct.