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Which is more stable stagger form of conformer s in gauche and anti and why?

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C_{2}

is rotated anti- clockwise

120^{\circ}

C_{2} - C_{3}

bond, the resulting conformer is

Q. For the stable conformer of

Z - C H_{2} - C H_{2} - Z

μ_{o b s} = \sum μ_{i} x_{i}

μ_{i}

is the dipole moment of the stable conformer and

x_{i}

is the mole fraction of that conformer.
If

μ_{s o l u t i o n} = 1 D

x_{a n t i} = 0.82

μ_{g a u c h e}

Q. Amongst the above conformations of 3-Aminopropanal

(P, Q, R, S)

, one of them is most stable. This can be attributed due to
(I) H-bonding in the conformer
(II) gauche conformation in the conformer
(III) anti conformation in the conformer
(IV) larger groups being separated by maximum distance in the conformer
The correct option is:

Q. Assertion :For

C_{2} H_{6}

staggered conformation is more stable than eclipsed. Reason: In staggered conformation, the bonded electrons have minimum repulsions.

Q. Assertion :Staggered conformation of ethane is most stable while eclipsed conformation is least stable. Reason: Staggered form has the least torsional strain and the eclipsed form has the maximum torsional strain.

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