Which is most stable ?

[N i C l_{4}]^{2 -}

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[N i (C N)_{4}]^{2 -}

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[P d (C N)_{4}]^{2 -}

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[P t (C N)_{4}]^{2 -}

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Solution

The correct option is C $[P t (C N)_{4}]^{2 -}$
Due to inert pair effect, $P t^{+ 2}$ is more stable and it have high charge density so $[P t (C N)_{4}]^{2 -}$ is most stable due to higher polarizibilty of cation.

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Similar questions

[N i (C N)_{4}]^{2 -}

[P t (C N)_{4}]^{2 -}

Among $[N i (C O)_{4}]$ , $[N i (C N)_{4}]^{- 2}$ and $[N i (C l)_{4}]^{- 2}$ :

N i (C O)_{4}

[N i (C N)_{4}]^{2 -}

[N i C l_{4}]^{2 -}

[N i (C N)_{4}]^{2 -}, [N i C l_{4}]^{2 -}

[N i (C O)_{4}]

[N i (C N)_{4}]^{- 2}

[N i C l_{4}]^{- 2}

e^{-}

[N i C N_{4}]^{- 2}

[N i C l_{4}]^{- 2}

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