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Chemical Reactivity (Group 1)

Which is not ...

Question

Which is not correctly matched?
(1) Basic strength of oxides:
$C s_{2} O < R b_{2} O < K_{2} O < N a_{2} O < L i_{2} O$
(2) Stability of carbonates:
$N a_{2} C O_{3} < K_{2} C O_{3} < R b_{2} C O_{3} < C s_{2} C O_{3}$
(3) Stability of bicarbonates:
$L i H C O_{3} < N a H C O_{3} < K H C O_{3} < R b H C O_{3} < C s H C O_{3}$
(4) Melting point:
$N a F < N a C l < N a B r < N a I$

1 and 4

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1 and 3

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1 and 2

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2 and 3

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Solution

The correct option is A 1 and 4
The basic nature of oxides increases down the group.
$C s_{2} O > R b_{2} O > K_{2} O > N a_{2} O > L i_{2} O$

Lattice energy $\propto \frac{1}{r^{+} + r^{-}}$
So more the L.E., more is the melting point.
$N a F > N a C l > N a B r > N a I$

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Similar questions

C s_{2} O < R b_{2} O < K_{2} O < N a_{2} O < L i_{2} O

N a_{2} C O_{3} < K_{2} C O_{3} < R b_{2} C O_{3} < C s_{2} C O_{3}

L i H C O_{3} < N a H C O_{3} < K H C O_{3} < R b H C O_{3} < C s H C O_{3}

N a F < N a C l < N a B r < N a I

C s_{2} O < R b_{2} O < K_{2} O < N a_{2} O < L i_{2} O

N a_{2} O_{2} < K_{2} O_{2} < R b_{2} O_{2} < C s_{2} O_{2}

L i H C O_{3} < N a H C O_{3} < K H C O_{3} < R b H C O_{3} < C s H C O_{3}

N a F < N a C l < N a B r < N a I

\to C s_{2} O < R b_{2} O < K_{2} O < N a_{2} O < L i_{2} O

\to N a_{2} O_{2} < K_{2} O_{2} < R b_{2} O_{2} < C s_{2} O_{2}

\to L i H C O_{3} < N a H C O_{3} < K H C O_{3} < R b H C O_{3} < C s H C O_{3}

\to N a F < N a C l < N a B r < N a I

C s_{2} O < R b_{2} O < K_{2} O < N a_{2} O < L i_{2} O

N a_{2} O_{2} < K_{2} O_{2} < R b_{2} O_{2} < C s_{2} O_{2}

L i H C O_{3} < N a H C O_{3} < K H C O_{3} < R b H C O_{3} < C s H C O_{3}

N a F < N a C l < N a B r < N a l

C s_{2} O < R b_{2} O < K_{2} O < N a_{2} O < L i_{2} O

N a_{2} O_{2} < K_{2} O_{2} < R b_{2} O_{2} < C s_{2} O_{2}

L i H C O_{3} < N a H C O_{3} < K H C O_{3} < R b H C O_{3} < C s H C O_{3}

N a F < N a C I < N a B r < N a I

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