Which is not obtained when metal carbides react with $H_{2} O$ ?

A l_{4} C_{3} + H_{2} O \to C H \equiv C H

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C a C_{2} + H_{2} O \to C H \equiv C H

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M g_{4} C_{3} + H_{2} O \to C H_{3} C \equiv C H

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B e_{2} C + H_{2} O \to C H_{4}

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Solution

The correct option is A $A l_{4} C_{3} + H_{2} O \to C H \equiv C H$
$A l_{4} C_{3} + H_{2} O \to 4 A l (O H)_{3} + C H_{4}$
Thus alkane is formed instead of acetylene. Thus option A is incorrect.

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Which is not obtained when metal carbides react with H2O?

The correct option is A Al4C3+H2O→CH≡CHAl4C3+H2O→4Al(OH)3+CH4Thus alkane is formed instead of acetylene. Thus option A is incorrect.

Which is not obtained when metal carbides react with $H_{2} O$ ?

The correct option is A $A l_{4} C_{3} + H_{2} O \to C H \equiv C H$
$A l_{4} C_{3} + H_{2} O \to 4 A l (O H)_{3} + C H_{4}$
Thus alkane is formed instead of acetylene. Thus option A is incorrect.