Which is not the vector form of Biot–Savart law-

- \to d B = \frac{K I (\to d l \times \to r)}{r^{3}}

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- \to d B = \frac{K I (\to d l \times^r)}{r^{2}}

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- \to d B = \frac{K I d l sin θ}{r^{2}}^n

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- \to d B = \frac{K I d l sin θ}{r^{2}}^r

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Solution

The correct option is D $- \to d B = \frac{K I d l sin θ}{r^{2}}^r$
As we know, $- \to d B ⊥$ both $\to d l$ and $\to r$

 Hence, $(D)$ is the correct answer.

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