The correct option is B Here pπ−pπ back bonding takes place
In metal carbonyls, both metal and CO acts as Lewis acid as well as base since both donate and accepts pair of electrons.
Carbon of CO donates electron pair to the empty d-orbital of metal and in return, metal donates electron pair to π∗ molecular orbital CO which results in dπ−pπ back bonding, i.e., sideways overlap of a filled orbital of the metal with empty antibonding π∗ (LUMO) orbital of CO.
Hence, option (d) is the wrong statement.