The correct option is D Here pπ−pπ back bonding takes place
In metal carbonyls, both metal and CO acts as Lewis acid as well as base.
carbon of CO donates electron pair to the empty orbital of metal and in return, metal donates electron pari to CO which involves dπ−pπ back bonding, i.e., sideways overlap of a filled orbital on the metal with empty antibonding π∗2py orbital of CO.