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Question

Which is the 14th term from the end of the arithmetic progression 7, 24, 41,..., 704?

A
483
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B
466
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C
517
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D
500
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Solution

The correct option is A 483

Given:
a = 7
d = 24 – 7 = 17
n = ?

Tn = a + (n-1)*d
704 = 7+ (n- 1)*17
704 = 7+ 17n – 17
704 = 17n – 10
714 = 17n
n = 714/17 = 42
Total number of terms = 42,
therefore 14th term from the end will be 29th term
N = 29
T29 = 7 + (29-1) * 17
= 7+28*17
= 7+476
T29 = 483


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