Question
Which is the 14th term from the end of the arithmetic progression 7, 24, 41,..., 704?
Which is the 14th term from the end of the arithmetic progression 7, 24, 41,..., 704?
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Solution
The correct option is A 483
Given:
a = 7
d = 24 – 7 = 17
n = ?
Tn = a + (n-1)*d
704 = 7+ (n- 1)*17
704 = 7+ 17n – 17
704 = 17n – 10
714 = 17n
n = 714/17 = 42
Total number of terms = 42,
therefore 14th term from the end will be 29th term
N = 29
T29 = 7 + (29-1) * 17
= 7+28*17
= 7+476
T29 = 483
Given:
a = 7
d = 24 – 7 = 17
n = ?
Tn = a + (n-1)*d
704 = 7+ (n- 1)*17
704 = 7+ 17n – 17
704 = 17n – 10
714 = 17n
n = 714/17 = 42
Total number of terms = 42,
therefore 14th term from the end will be 29th term
N = 29
T29 = 7 + (29-1) * 17
= 7+28*17
= 7+476
T29 = 483
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