Which is the best way of preparing propene from chloroethene?

C H_{2} = C H C l + C H_{3} C l N a / E t h e r - ----- \to H e a t

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C H_{2} = C H C l + (C H_{3})_{2} C u L i \to

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C H_{3} C l + (C H_{2} = C H C l)_{2} C u L i \to

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C H_{2} = C H C l + C H_{3} L i \to

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Solution

The correct option is C $C H_{3} C l + (C H_{2} = C H C l)_{2} C u L i \to$
The reaction of option C is the best way of preparing propene from chloroethene
$S_{N} 2$ reactions occur most efficiently with $C H_{3} C l$ . Methyl chloride reacts with lithium dichloroethenyl cuprate to form propene

$C H_{3} C l + (C H_{2} = C H C l)_{2} C u L i \to$ $C H_{3} - C H = C H_{2}$

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