Question

Which is the correct answer for the following expression:
$\text{Add:}\frac{7}{12}and\frac{9}{8}$

• A. $\frac{41}{24}$
• B. $\frac{24}{41}$
• C. $\frac{16}{12}$
• D. $\frac{16}{8}$

Answer 1

The correct option is A $\frac{41}{24}$

As these are unlike fractions, we need to convert the fractions into like fractions.

To convert: Let's find the LCM of the denominators (12, 8)
Multiples of 12 : 12, 24, 36...
Multiples of 8 : 8, 16, 24...
LCM (12, 8) = 24

Multiply $\frac{7}{12}$ with 2 to convert the denominator into 24, we get:

$\frac{7}{12}$ = $\frac{7\times 2}{12\times 2}$ = $\frac{14}{24}$

Multiply $\frac{9}{8}$ with 3 to convert the denominator into 24, we get:

$\frac{9}{8}$ = $\frac{9\times 3}{8\times 3}$ = $\frac{27}{24}$


Now add these two fractions,
$\therefore$ $\frac{7}{12}+\frac{9}{8}=\frac{14}{24}+\frac{27}{24}=\frac{14+27}{24}=\frac{41}{24}$

Hence, $\frac{7}{12}+\frac{9}{8}$ = $\frac{41}{24}$