Which is the correct arrangement of molecule regarding dipole moment?

B F_{3} = N H_{3} = N F_{3}

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B F_{3} > N H_{3} > N F_{3}

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B F_{3} < N H_{3} < N F_{3}

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B F_{3} < N F_{3} < N H_{3}

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Solution

The correct option is D $B F_{3} < N F_{3} < N H_{3}$
$B F_{3}$ has planar and symmetrical structure so it has zero dipole moment. As the electronegativity difference is N and F is large, it has lesser dipole moment and as the electronegativity difference in N and H is more, it has more dipole moment, so $N H_{3}$ has most dipole moment

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