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Balancing Redox Reaction

Which is the ...

Question

Which is the correct expression of van't Hoff factor for association of electrolyte?
Here,
n is the number of molecules associate to form n-mer
$β$ is the degree of dissociation

A

i = 1 + [\frac{1}{n} - 1] β

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B

i = 2 + [\frac{1}{n} - 1] β

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C

i = 1 + [n - 1] β

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D

i = 1 + [\frac{1}{n} + 1] β

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Solution

The correct option is A $i = 1 + [\frac{1}{n} - 1] β$
Association of electrolyte:
$n A ⇌ A_{n}$
$t = 0 : C 0$
$t = t_{e q} : C (1 - β) \frac{c β}{n}$

At equilibrium,
$Net concentration = C - C β + \frac{c β}{n}$
$= C [1 + [\frac{1}{n} - 1] β]$

$i = \frac{C [1 + [\frac{1}{n} - 1] β]}{C}$
$i = 1 + [\frac{1}{n} - 1] β$

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Similar questions

The electrolyte solutions show abnormal colligative properties. To account for this effect we define a quantity called the Van't Hoff factor given by :

i = \frac{Actual number of particles in solution after dissociation/association}{Number of formula units initially dissolved in solution}

i = 1

(for non-electrolytes)

i > 1

(for non-electrolytes, undergoing dissociation)

i < 1

(for solutes, undergoing dissociation)

Answer the following questions:

A solution of benzoic acid is dissolved in benzene such that it undergoes molecular association and its molar mass approaches 244. The benzoic molecules will exist as :

Q. Which is the correct expression of van't Hoff factor for association of electrolyte?
Here,
n is the number of molecules associate to form n-mer

β

is the degree of dissociation

Q. Which is the correct expression of van't Hoff factor for dissociation of electrolyte?
Here,
n is the number of ions formed from one formula unit of the substance

Q. The Van't Hoff factors

i

for an electrolyte which undergoes dissociation and association in solvents are respectively:

Q. The degree of dissociation

(α)

of a weak electrolyte,

A_{x} B_{y}

is related to van't Hoff factor (i) by the expression:

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Balancing Redox Reaction

Standard VII Chemistry

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