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Question

Which is the correct increasing order of reducing power of the given metals?
Standard electrode potentials:
K++eK; E0=2.93 VAg++eAg; E0=0.80 VHg2+2+e2Hg; E0=0.79 VMg2++eMg; E0=2.37 VCr3++eCr; E0=0.74 V

A
K<Mg<Cr<Hg<Ag
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B
Ag<Hg<Cr<Mg<K
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C
Hg<Ag<Cr<Mg<K
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D
K<Mg<Cr<Ag<Hg
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Solution

The correct option is B Ag<Hg<Cr<Mg<K
Standard reduction potentials (SRP) of the half cell electrodes are calculated and arranged in a series of increasing order which is known as electrochemical series.
The standard electrode potential of H+/H2 couple is zero.


A positive E0 signifies that it has high tendency to get reduced and the redox couple is a stronger oxidising agent than the H+/H2 couple.

Here, a negative E0 signifies that it has high tendency to get oxidised and the redox couple is a stronger reducing agent than the H+/H2 couple.

Hence, the increasing order of reducing power of the metals are,
Ag<Hg<Cr<Mg<K

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