Which is the correct increasing order of reducing power of the given metals?
Standard electrode potentials: K++e−→K;E0=−2.93VAg++e−→Ag;E0=0.80VHg2+2+e−→2Hg;E0=0.79VMg2++e−→Mg;E0=−2.37VCr3++e−→Cr;E0=−0.74V
A
K<Mg<Cr<Hg<Ag
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B
Ag<Hg<Cr<Mg<K
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C
Hg<Ag<Cr<Mg<K
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D
K<Mg<Cr<Ag<Hg
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Solution
The correct option is BAg<Hg<Cr<Mg<K Standard reduction potentials (SRP) of the half cell electrodes are calculated and arranged in a series of increasing order which is known as electrochemical series.
The standard electrode potential of H+/H2 couple is zero.
A positive E0 signifies that it has high tendency to get reduced and the redox couple is a stronger oxidising agent than the H+/H2 couple.
Here, a negative E0 signifies that it has high tendency to get oxidised and the redox couple is a stronger reducing agent than the H+/H2 couple.
Hence, the increasing order of reducing power of the metals are, Ag<Hg<Cr<Mg<K