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Question

Which is the correct thermal stability order
for H2E (E=O,S,Se,Te and Po)?

A
H2S< H2O< H2Se< H2Te< H2Po
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B
H2O< H2S< H2Se< H2Te< H2Po
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C
H2Po< H2Te< H2Se< H2S< H2O
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D
H2Se< H2Te< H2Po< H2O< H2S
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Solution

The correct option is C H2Po< H2Te< H2Se< H2S< H2O
On going down the group, the thermal stability of H2E decreases due to the decrease in the H–E bond energy.
Thus, the order is:
H2Po< H2Te< H2Se< H2S< H2O

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