Question

Which is the correct thermal stability order for $H_{2}E(E=O,S,Se,TeandPo)?$

<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> NEET 2019

• A. $H_{2}Po<H_{2}Te<H_{2}Se<H_{2}S<H_{2}O$
• B. $H_{2}O<H_{2}S<H_{2}Se<H_{2}Te<H_{2}Po$
• C. $H_{2}Se<H_{2}Te<H_{2}Po<H_{2}O<H_{2}S$
• D. $H_{2}S<H_{2}O<H_{2}Se<H_{2}Te<H_{2}Po$

Answer 1

The correct option is A $H_{2}Po<H_{2}Te<H_{2}Se<H_{2}S<H_{2}O$

On going down the group thermal stability order for $H_{2}E$ decreases because $H-E$ bond energy decreases.

$\therefore$ Order of stability would be:-

$H_{2}Po<H_{2}Te<H_{2}Se<H_{2}S<H_{2}O$