Which is the counter ion in $[P d (N H_{3})_{4}]^{2 +} 2 C l^{-}$ ?

P d^{2 +}

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[P d (N H_{3})_{4}]^{2 +}

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C l^{-}

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It does not have a counter ion

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Solution

The correct option is C $C l^{-}$
In coordination compounds, the ions outside the coordination sphere (square bracket) are called counter ions, and the species within the square bracket are the coordination entities.
In the given compound ammonia is the coordinating ligand and chloride counter ion.
Thus, option (c) is the correct answer.

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