Question

Which is the factored form of
${3a}^2-24ab+48b^2$

• A. (3a−8b) (a−6b)
• B. (3a−16 b) (a−3b)
• C. 3(a−4b) (a−4b)
• D. 3(a−8b) (a−8b)

Answer 1

The correct option is C

3(a−4b) (a−4b)

By factorizing, we get:
$3a^2-8ab+16b^2=3(a^2-2a.4b+{4b}^2)=(3a-4{)}^2$