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Question

Which is the factored form of
3a224ab+48b2

A

(3a−8b) (a−6b)

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B

(3a−16 b) (a−3b)

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C

3(a−4b) (a−4b)

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D

3(a−8b) (a−8b)

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Solution

The correct option is C

3(a−4b) (a−4b)


By factorizing, we get:
3a28ab+16b2=3(a22a.4b+4b2)=(3a4)2


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