wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Which is the greatest number that will divide 137, 182 and 422, leaving the remainder 2 in each case?

A
15
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
45
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
20
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
90
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 15
Here, 137 – 2 =135, 182 – 2 = 180, 422 – 2 = 420
Therefore, the required number is the HCF of the numbers 135, 180, 420.
135=3×3×3×5180=2×2×3×3×5420=2×2×3×5×7
HCF of 135, 180 and 420=3×5=15

flag
Suggest Corrections
thumbs-up
20
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Special Factors and Multiples
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon