Question

Which is the greatest number that will divide $37;50,123$ leaving remainder $1,2$ and $3$, respectively?

• A. $9$
• B. $10$
• C. $15$
• D. $12$

Answer 1

The correct option is D $12$

$37-1=36,50-2=48$,
$123-3=120$
HCF of $36,48$ and $120=12$
$\therefore$ required number $=12$.