Which is the last element in the series of the actinoids? Write the electronic configuration of this element. Comment on the possible oxidation state of this element.

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Solution

Lawrencium ( $Z = 103$ ) is the last element in the actinoid series.

Its electronic configuration is $[R n]^{86} 5 f^{14} 6 d^{1} 7 s^{2}$ .

The most common oxidation state displayed by it is $+ 3$ because after losing $3$ electrons it attains stable $f^{14}$ configuration.

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Which is the last element in the series of the actinoids? Write the electronic configuration of this element. Comment on the possible oxidation state of this element.

Lawrencium (Z=103) is the last element in the actinoid series. Its electronic configuration is [Rn]865f146d17s2. The most common oxidation state displayed by it is +3 because after losing 3 electrons it attains stable f14 configuration.

Lawrencium ( $Z = 103$ ) is the last element in the actinoid series.

Its electronic configuration is $[R n]^{86} 5 f^{14} 6 d^{1} 7 s^{2}$ .

The most common oxidation state displayed by it is $+ 3$ because after losing $3$ electrons it attains stable $f^{14}$ configuration.