Question

Which is the last member of the Lanthanide series?

Answer 1

Lanthanide series:

• This series belongs to f-block elements.
• The members of this series are Lanthanum (La), Cerium (Ce), Praseodymium (Pr), Neodymium (Nd), Promethium (Pm), Samarium (Sm), Europium (Eu), Gadolinium (Gd), Terbium (Tb), Dysprosium (Dy), Holmium (Ho), Erbium (Er), Thulium (Tm), Ytterbium (Yb), and Lutetium (Lu).
• Lanthanum closely resembles the Lanthanoids and is usually mentioned with the general symbol Ln in any discussion of Lanthanoids.
• Lanthanoids resemble one another more closely than do members of any ordinary series of transition elements.
• Their chemistry provides a unique opportunity for studying the effect of small changes in size and nuclear charge as they are stable in one oxidation state.

Lanthanide series last member:

• The last member of the Lanthanide series is Lutetium (Lu) with atomic number 71.
• The electronic configuration is $4{\mathrm{f}}^{14}5{\mathrm{d}}^{1}6{\mathrm{s}}^2$ and ionic radius is less than 86pm.