Which is the least number that must be added to 1856 to make it divisible by 7,12 and 16?

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160

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167

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None of these

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Solution

The correct option is B 160
LCM of (7,12 & 16) is 336.
Now, 1856 when divided by 336 gives the remainder as 176.
So, 336-176 i.e. 160 must be added to 1856 to make it divisible by 336.

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