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Question

Which is the least number which when divided by 6, 15 and 18 leave remainder 5 in each case?

A
95
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B
185
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C
65
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D
100
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Solution

The correct option is A 95

The least number which is divisible by 6, 15 and 18 is the LCM of 6, 15 and 18.
6=2×315=3×518=2×3×3
LCM of 6,15 and 18=2×5×3×3=90
Therefore,
The least number which when divided by 6, 15 and 18 leave remainder 5 in each case will be 90 + 5 = 95


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