Which is the least number which when divided by 6, 15 and 18 leave remainder 5 in each case?
A
95
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B
185
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C
65
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D
100
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Solution
The correct option is A 95
The least number which is divisible by 6, 15 and 18 is the LCM of 6, 15 and 18. 6=2×315=3×518=2×3×3 LCM of 6,15and18=2×5×3×3=90 Therefore, The least number which when divided by 6, 15 and 18 leave remainder 5 in each case will be 90 + 5 = 95