Which is the most suitable reagent among the following distinguish compound (3) from the others ?
$C h_{3} C = C - C H_{3}$
$C H_{3} C H_{2} - C H_{2} - C H_{3}$
$C H_{3} C H_{2} C = C H$
$C H_{3} C H = C H_{2}$

Bromine in carbon tetrachloride

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Bromine in acetic acid solution

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Alk .

K M n O_{4}

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Ammonical silver nitrate

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Solution

The correct option is D Ammonical silver nitrate
Terminal alkynes give white colour with Ammonical $A g N O_{3}$

$C H_{3} - C H_{2} - C \equiv C H N H_{4} / A g N O_{3} ⟶ C H_{3} - C H_{2} - C \equiv C^{⊝} A g^{\oplus}      (W h i t e)$

Suggest Corrections

Similar questions

(i) C H_{3} - C \equiv C - C H_{3}

(i i) C H_{3} - C H_{2} - C H_{2} - C H_{3}

(i i i) C H_{3} - C H_{2} - C \equiv C H

(i v) C H_{3} - C H = C H_{2}

1. C H_{3} - C \equiv C - C H_{3}

2. C H_{3} - C H_{2} - C H_{2} - C H_{3}

3. C H_{3} - C H_{2} C \equiv C H

4. C H_{3} - C H = C H_{2}

(i) C H_{3} - C \equiv C - C H_{3}

(i i) C H_{3} - C H_{2} - C H_{2} - C H_{3}

(i i i) C H_{3} - C H_{2} - C \equiv C H

(i v) C H_{3} - C H = C H_{2}

C H_{3} C H_{2} C \equiv C H

C H_{3} C \equiv C C H_{3}

C H_{3} C H_{2} C H_{2} C H_{3}

C H_{3} C H = C H_{2}

A g N O_{3}

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