When 1 mole of CrCl3.6H2O is treated with excess of AgNO3, 3 moles of AgCl are obtained. The formula of the complex is (a) [CrCl3(H2O)3]3H2O (b) [CrCl3(H2O)4]Cl2.2H2O (c) [CrCl3(H2O)5]Cl2.H2O (d) [Cr(H2O)6]Cl3