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Question

Which isomerism is shown by the given compound?
1022713_e595675cc7c34a1387d7e2ef7e4d5550.png

A
E-isomer
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B
Z-isomer
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C
Cis-isomer
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D
Trans-isomer
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Solution

The correct option is B Z-isomer
The given compound shows E and Z isomer because cis and trans isomers are not possible as two groups are not same on the opposite terminals. And E and Z isomers are possibly across the middle double bond.
1106489_1022713_ans_d5bda92ffe9f48dd9a30a2b006cd6d82.png

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