Which least number should be added to 1000 so that the sum is exactly divisible by 45?

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Solution

Here, on dividing $1000$ by $45$ we get $10$ as the remainder
$4522 100090_10090_10$
Thus, the Required sum = $1000$ $+ (- 10)$
= $1000$ $- 10$
= $990$
Hence, if we add $(- 10)$ then the sum is divisible by $45$

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