Which ligand is expected to be bidentate?

C_{2} O_{4}^{2 -}

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C H_{3} C \equiv N

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B r^{-}

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C H_{3} N H_{2}

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Solution

The correct option is A $C_{2} O_{4}^{2 -}$
Oxalate ion may bind with central metal atom through two oxygen atoms containing negative charge.

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A bidentate ligand is :

[C H_{3} N H_{2}]

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