Question

Which logic gate is represented by the following truth table ?

A	B	$Y$
0	0	1
0	1	1
1	0	1
1	1	0

• A. AND
• B. NOR
• C. NAND
• D. OR

Answer 1

The correct option is C NAND

For an AND gate,

A	B	$Y=A\cdot B$
0	0	0
0	1	0
1	0	0
1	1	1

Now $\text{NAND =AND+NOT}$
$\Rightarrow$ NOT applied on AND output. So$Y=\overline{A.B}$

$Y=\overline{A.B}$

1

1

1

0

Hence, $\left(D\right)$ is the correct answer.

$\begin{array}{c}\text{Why this question?}\\ \text{Caution : Becareful,here NOT operation is}\\ \text{applied after AND operations.}\\ \end{array}$