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Question

Which logic gate is represented by the following truth table ?

A B Y
0 0 1
0 1 1
1 0 1
1 1 0

A
AND
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B
NOR
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C
NAND
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D
OR
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Solution

The correct option is C NAND
For an AND gate,

A B Y=AB
0 0 0
0 1 0
1 0 0
1 1 1

Now NAND =AND+NOT
NOT applied on AND output. SoY=¯¯¯¯¯¯¯¯¯¯¯A.B
Y=¯¯¯¯¯¯¯¯¯¯¯A.B
1
1
1
0

Hence, (D) is the correct answer.

Why this question?Caution : Becareful,here NOT operation is applied after AND operations.

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