Question

Which metal is refined by Van-Arkel method?

• A. $Ni$
• B. $Al$
• C. $Si$
• D. $Ti$

Answer 1

The correct option is D $Ti$

$TiorZr$ metal is refined by the Van-Arkel method. Metal is converted (by heating with little iodine) to volatile (covalent) tetraiodide which is then decomposed ( by electrically heating above 1800 K with tungsten filament ) to pure metal which is deposited on a tungsten filament.
Reactions:
$Zr+2I_2\to \underset{\text{More Covalent}\text{Volatilises}}{Zr{I}_2}$
$Zr{I}_2\to \underset{\text{Pure Metal}}{Zr}+2I_2$