Which metal(s) can be used to produce electrons by the photoelectric effect from given source of light ?

Barium only

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Barium or lithium

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Lithium, tantalum or tungsten

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Tungsten or tantalum

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D Barium or lithium
Photoelectric effect
$K E_{m a x} = h v - W_{o}$
The minimum energy to knock out electrons
$K E \geq 0$
$h v > W_{o}$
$\frac{h c}{λ} > W_{o}$ ------------------(1)
Here, available energy = $E = \frac{h c}{λ} = 2.75 e V$
For Photoelectric effect
$W_{o} < 2.75 e V$ by (1)
From the table, only true for Ba and Li

Suggest Corrections

Similar questions

A student performs an experiment to observe photoelectric effect by shining light on a metal surface. The light source limits light of wavelength 450nm. The table given below lists the available metals and their corresponding work functions
$\begin{matrix} M e t a l & ϕ (e v) T u n g s t e n & 4.5 L i t h i u m & 2.3 B a r i u m & 2.5 T a n t a l u m & 4.2 \end{matrix}$

Which of the above metals can be used to produce electrons by the photoelectric effect from the given source of light?

Q. A physicist wishes to eject electrons by shining light on a metal surface. The light source emits light of wavelength of 450 nm. The table lists the only available metal and their work functions.

\begin{matrix} M e t a l & W_{0} (e V) B a r i u m & 2.5 L i t h i u m & 2.3 T a n t a l u m & 4.2 T u n g s t e n & 4.5 \end{matrix}

Which metal(s) can be used to produce electrons by the photoelectric effect from given source of light?

According to the experiment of photoelectric effect, the number of electrons ejected from the metal surface is proportional to the intensity or brightness of light.

A physicist wishes to eject electrons by shining light on a metal surface. The light source emits light of wavelength of 450 nm. The table lists the only available metal and their work functions.
$\begin{matrix} M e t a l & W_{0} (e V) B a r i u m & 2.5 L i t h i u m & 2.3 T a n t a l u m & 4.2 T u n g s t e n & 4.5 \end{matrix}$

Which option correctly identifies the metal that will produce the most energetic electrons and their energies?

Q. The maximum wavelength of light that can be used to produce photoelectric effect on a metal is 250 nm. The maximum kinetic energy of the electrons in joule, emitted from the surface of the metal when a beam of light of wavelength 200 nm is used :

Join BYJU'S Learning Program

Which metal(s) can be used to produce electrons by the photoelectric effect from given source of light ?

The correct option is D Barium or lithiumPhotoelectric effectKEmax=hv−WoThe minimum energy to knock out electronsKE≥0hv>Wohcλ>Wo ------------------(1)Here, available energy = E=hcλ=2.75eVFor Photoelectric effectWo<2.75eV by (1)From the table, only true for Ba and Li