Which mixture of gases at room temp does not obey daltons law of partial pressure?

H e + N e + O_{2}

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C O_{2} + N_{2} + O_{2}

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N H_{3} + H C l + O_{2}

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N_{2} + O_{2} + C H_{4}

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Solution

The correct option is B $N H_{3} + H C l + O_{2}$
The mixture of $N H_{3}$ and $H C l$ at room temperature does not obey Dalton's law of partial pressure.

$N H_{3}$ and $H C l$ react spontaneously when putting together within the same apparatus. If they react, then the volume obviously changes. Which will not result in the pressure that you would predict if the two gases don't react and remained as separate entities.

Hence, the correct option is $C$

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\begin{matrix} Gas & a (L^{2} a t m m o l^{- 2}) N_{2} & 1.390 O_{2} & 1.360 N H_{3} & 4.170 C H_{4} & 2.253 \end{matrix}

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