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Question

Which mixture of the solution will lead to the formation of negatively charged colloids of [AgI]I- sol?


A

50mLof1MAgNO3+50mlof2MKI

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B

50mLof2MAgNO3+50mlof1.5MKI

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C

50mLof1MAgNO3+50mlof1.5MKI

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D

50mLof0.1MAgNO3+50mlof0.1MKI

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Solution

The correct option is C

50mLof1MAgNO3+50mlof1.5MKI


Explanation for the correct option:

(C) 50mLof1MAgNO3+50mlof1.5MKI

  • The colloidal sol AgI is prepared by adding KI solution to the AgNO3 solution till KI is in slight excess, iodide ion I will be absorbed in the surface of AgI particles thereby giving them a negative charge:

AgI+IAgI:I

  • The reaction that takes place when AgNO3 and KI react together can be depicted as:
    AgNO3(aq)+KI(s)AgI(aq)+KNO3(aq)
  • Thus, for surrounding the silver iodide with iodide ion, the concentration of KI must be slightly more than AgNO3. Thus, the concentration will be 50mLof1MAgNO3+50mlof1.5MKI.

Explanation for incorrect options:

The concentration of KI must be slightly more than AgNO3. Thus, options A, B, and C stand incorrect.

Hence, the correct option is C i.e. 50mLof1MAgNO3+50mlof1.5MKI.


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