Which molecule is relatively more stable?

O_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

H_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

L i_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

N_{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $N_{2}$
Nitrogen molecule ( $N_{2}$ ) is relatively more stable. Each $N$ atom has completed its octet and there is a triple bond between two $N$ atoms. In other molecules, there is either a single bond or a double bond between two atoms. A triple bond is stronger than a single or double bond.

Suggest Corrections

Similar questions

Q. At

S T P

the order of mean square velocity of molecules of

H_{2}, N_{2}, O_{2}

and

H B r

is-

$S_{1}$ : Bond order of $O_{2}^{-}$ is more than $O_{2}^{+}$
$S_{2}$ : $N O^{+}$ is more stable than $N_{2}^{+}$
$S_{3}$ : $C_{2}$ is more stable than $C_{2}^{+}$
State, in order, whether $S_{1}$ , $S_{2}$ , $S_{3}$ are true or false ?

Q. At

S T P

the order of root mean square velocity of molecule of

H_{2}

N_{2}

O_{2}

and

H B r

is :

Q. At

S T P

, the order of

R M S

velocities of

H_{2}, N_{2}, O_{2}

and

H B r

molecules is:

Q. Assertion :

H_{2}

molecule is more stable than

H e - H

molecule. Reason: The antibonding electron in

H e - H

molecule decreases the bond order and there by stability.

Join BYJU'S Learning Program